25=b^-2/3

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Solution for 25=b^-2/3 equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

25 = (b^-2)/3 // - (b^-2)/3

25-((b^-2)/3) = 0

-1/3*b^-2 = -25 // : -1/3

b^-2 = 75

-2 < 0

1/(b^2) = 75 // * b^2

1 = 75*b^2 // : 75

1/75 = b^2

b^2 = 1/75 // ^ 1/2

abs(b) = (1/75)^(1/2)

b = (1/75)^(1/2) or b = -(1/75)^(1/2)

b in { (1/75)^(1/2), -(1/75)^(1/2) }

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